Shell Script to Print Only First / Last Words in all Lines of a Text File

I have a text file and I wanted to print only first and last words of the file.

My sample input file is with following data

$ cat dat

 MONTH YYYY WK Mo Tu We Th Fr Sa Su

01-JAN 2013 01    01 02 03 04 05 06

01-JAN 2013 02 07 08 09 10 11 12 13

01-JAN 2013 03 14 15 16 17 18 19 20

01-JAN 2013 04 21 22 23 24 25 26 27

01-JAN 2013 05 28 29 30 31

02-FEB 2013 05             01 02 03

02-FEB 2013 06 04 05 06 07 08 09 10

02-FEB 2013 07 11 12 13 14 15 16 17

02-FEB 2013 08 18 19 20 21 22 23 24

02-FEB 2013 09 25 26 27 28

Method 1: Using cut and while loop

while read -r line

 do

 echo $line|cut -d " " –f1,`echo $line|wc -w`

 done

Method 2: Using awk command.

$ awk '{ print $1” “ $NF }' dat

Output would be like this

MONTH Su

01-JAN 06

01-JAN 13

01-JAN 20

01-JAN 27

01-JAN 31

02-FEB 03

02-FEB 10

02-FEB 17

02-FEB 24

02-FEB 28